LCM and HCF Practice Test 4

Question : 19 of 40

Marks: +1, -0

The HCF and LCM of two numbers are respectively 8 and 1,728. How many such pairs of numbers are there?

Solution:

Let the two numbers be x and y
HCF = 8
LCM = 1,728

8x× 8y= 8× 1,728

xy = 216

Number of such possible pairs is 2, i.e. (1, 216) and (8, 27).

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