LCM and HCF Practice Test 4

Question : 12 of 40

Marks: +1, -0

Two numbers are in the ratio 2 : 3. If their HCF is 27, then their LCM will be:

Solution:

Let the two numbers be 2x and 3x x = HCF = 27
So the numbers are 27 × 3 and 27 × 4 = 54 and 81

\LCM = {\Product \of \numbers}/{\HCF}

LCM

={54×81}/27=162

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