LCM and HCF Practice Test 3

One of the number = 240
Sum of LCM and HCF = 1,740
LCM + HCF = 1,740 ......(1)
or LCM = 28 (HCF)
Put this value in equation (1)
HCF + 28(HCF) = 1,740
29 (HCF) = 1,740
So, HCF $=\frac{1740}{29}=60$
HCF = 60
We know that,
Product of two numbers = Product of HCF and LCM.
240 × y = 28 (HCF) × 60
240y = 28 × 60 × 60
$\mathit{y}=\frac{28\times 60\times 60}{240}=420$
The sum of the digits of the other numbers is 6.