LCM and HCF Practice Test 2

Product of two numbers = their HCF × their LCM
2160 = 12 × LCM
$\therefore \mathit{L}\mathit{C}\mathit{M}=\frac{2160}{12}=180$
Therefore such pairs of numbers in which product of numbers is 2160 and HCF is 12 will be only 2.
i.e., 12 × 180 and 36 × 60.