LCM and HCF Practice Test 1

L.C.M. of the given numbers 12, 18 and 24 ∴ L.C.M. = 2 × 2 × 3 × 3 × 2 = 72
∴ The required 3-digit number which is smallest as well as divisible by 12, 18, and 24 will be 72 × 2 = 144.