Heights and Distances Practice Test 2

Question : 15 of 24

Marks: +1, -0

Distance between the two building is 140meters. From the top of the first building theangle of elevation when seen from the top ofsecond building is 60°. Find the height of firstbuilding if the height of second building is45 m.

$(140√3 + 45) m$
$(140√ - 45)m$
$(70√3 + 45) m$
All of the above
None of these

Validate

Solution:

In ΔABE,

h/140=√3

Total height of the tower

= AB + BC = (140√3 + 45)

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