Heights and Distances Practice Test 2

Question : 10 of 24

Marks: +1, -0

A tower is 60 m. An observer from the top ofthe tower makes an angle of depression of30° at the base of the building and angle ofdepression of 60° at the top of the building.What is the height of the building?

40 m
80 m
30 m
All of the above
None of these

Validate

Solution:

In ΔACD,

60/x=\tan60°=√3

⇒x=60/√3

......(1)
In ΔABE,

{60-h}/x=\tan30°=1/√3

⇒x=√3(60-h)

......(2)

⇒60/√3=√3(60-h)

h=40m

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