Heights and Distances Practice Test 1

Question : 6 of 40

Marks: +1, -0

The angle of elevation of a building changesfrom 45° to 60° when a man walks 20 mtowards it. What is the height of the building?

Solution:

The required height

={x\tanθ_1\tanθ_2}/{\tanθ_2-\tanθ_1}

={30\tan45°\tan60°}/{\tan60°-\tan45°}

={20×1×√3}/{√3-1}={20√3}/{√3-1}m

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