Heights and Distances Practice Test 1

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Question : 29 of 40

Marks: +1, -0

From the foot of a tower on level ground, the angle of elevation of the top of the tower is 30° at a distance of

90√3

m. Find the height of the tower.

90 m
60 m
80 m
All of the above
None of these

Solution:

In ΔABC,

{AB}/{BC}=\tan30°

{AB}/{90√3}=1/√3

{AB}={90√3}/√3=90m

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