Heights and Distances Practice Test 1

Question : 20 of 40

Marks: +1, -0

From a point P on a level ground, the angle of elevation of the top of a tower is 30°. If the toweris 100 m high, find the distance of point P from the foot of the tower.

100 m
173 m
200 m
273 m

Validate

Solution:

Let, AB = 100 m be the height of a tower, P is a point on the ground such that ∠APB = 30°
From right triangle ABP,
BP = 100 cot 30° =

100 √3

= 100 × 1.73 = 173 m

Go to Question:

Prev Question

Next Question