Heights and Distances Practice Test 1

Question : 17 of 40

Marks: +1, -0

Sujata at a distance of 30 m saw a butterfly.The butterfly is at a height of 80 m above thewindow. How far is the butterfly from Sujata?

Solution:

H^2 = P^2 + B^2= (80)^2 + (30)^2

= 6,400 + 900 = 7,300

H = √7300 = 85.4 m

Go to Question:

Prev Question

Next Question