Geometry Practice Test 7

Question : 8 of 28

Marks: +1, -0

Let ABCD is a quadrilateral. Let the diagonals AC and BD meet at O. Let the perpendicular drawn from A to CD meet CD at E. Further, AO : OC = BO : OD, AB = 30 cm, CD = 40 cm and the area of the quadrilateral ABCD is 1,050

cm^2

.
What is the area of the triangle ADC equal to?

300 $cm^2$
450 $cm^2$
600 $cm^2$
None of these

Validate

Solution:

Area of triangle ADC =

1/2

× base × height
=

1/2

× 40 × 30 = 600

\cm^2

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