Geometry Practice Test 7

In this BC || AE
AC is a transversal line.
BC = AC
⇒ ∠ CBA = ∠CAB = 65°
ΔABC = ∠CBA +∠CAB+∠ACB = 180°
∠ACB = 180° − (65° + 65°) = 50°
∠ACB = ∠CAE {angles with two parallel line with the same transversal line)
∠CAE = 50°