Geometry Practice Test 6

Construct AO bisector of ∠A
In ΔAOE
∠EAO + ∠AOE + ∠OEA = 180°
∠AOE = 180° − (35° + 90)
∠AOE = 55°
Similarly, ∠AOF = 55°
∠FOE = ∠AOE +∠AOF = 55° + 55° = 110°

∠FOE = ∠BOC = 110°
{vertically opposite angles}