Geometry Practice Test 6

Question : 2 of 39

Marks: +1, -0

The ratio of length of each equal side and the third side of an isosceles triangle is 3 : 4. If the area of the triangle is 18

√5

square unit, the third side is

Solution:

Area of the triangle =

18√5

Ratio of equal side and third side = 3a : 4a

b/4 √{4a^2-b^2}

18√5

{4a}/4 √{4(3a)^2-(4a)^2}

18√5

a√{36a^2-16a^2}

18√5

a2a√5

18√5

2a^2

= 18

a^2

= 9
a = 3
Third side = 4a = 4 × 3 = 12 units

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