Geometry Practice Test 6

Question : 17 of 39

Marks: +1, -0

Triangle PQR circumscribes a circle with centre O and radius r cm such that ∠PQR = 90°. If PQ = 3 cm, QR = 4 cm, then the value of r is:

Solution:

∠PQR = 90°

PQ = 3 cm
QR = 4 cm
By Pythagoras theorem,

(PQ)^2+(QR)^2

(PR)^2

(3)^2+(4)^2

(PR)^2

√{9+16}

= Pr
D = PR = 5 cm
Radius = r = 2.5 cm

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