Geometry Practice Test 5

Question : 26 of 40

Marks: +1, -0

Three parallel lines are cut by two transversals as shown in the given figure. If AB = 2 cm, BC = 4 cm and DE = 1.5 cm, then the length of EF is:

Solution:

AB = 2 cm BC = 4 cm
DE = 1.5 cm EF = x cm

{AB}/{BC}

{DE}/{EF}

2/4

{1.5}/x

⇒ 2 × x = 1.5 × 4
x =

{6.0}/2

= 3.0 cm

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