Geometry Practice Test 3

AB = 8 cm
OP ⊥ AB
AP = PB = 4 cm

CD = 6 cm
OQ ⊥ CD
CQ = QD = 3 cm.
OC = OB = 5 = radius.
In Δ OPB and Δ OQC
${\left(\mathit{O}\mathit{P}\right)}^2$ = ${\left(\mathit{O}\mathit{B}\right)}^2-{\left(\mathit{P}\mathit{B}\right)}^2$
or ${\left(\mathit{O}\mathit{Q}\right)}^2$ = ${\left(\mathit{O}\mathit{C}\right)}^2-{\left(\mathit{C}\mathit{Q}\right)}^2$
${\left(\mathit{O}\mathit{P}\right)}^2$ = ${\left(5\right)}^2-{\left(4\right)}^2$ or $\mathit{O}{\mathit{Q}}^2$ = ${\left(5\right)}^2-{\left(3\right)}^2$
$\mathit{O}{\mathit{P}}^2$ = 25 - 16 or $\mathit{O}{\mathit{Q}}^2$ = 25 - 9
OP = $\sqrt{9}$ or OQ = $\sqrt{16}$
OP = 3 cm OQ = 4 cm
OP + OQ = PQ
PQ = 3 + 4 = 7 cm