Geometry Practice Test 2

PA = PQ (tangent drawn at P and Q on the circumference of a circle)
⇒ ∠APQ = ∠AQP
In Δ PQA ,
⇒ ∠AQP +∠APQ+∠PAQ = 180°
x + x +∠PAQ = 180°
2x + 68° = 180°
2x = 180° − 68°
2x = 112
x = 56°