Geometry Practice Test 1

Question : 14 of 40

Marks: +1, -0

The centric of an equilateral ΔABC is G. If AB = 9 cm, the length of AG (in cm) is:

Solution:

In an equilateral triangle, centric and centroid will lie on the same point.
Side S = 9 cm.
H =

√3/2 a

H =

{√3 × 9}/2

It divides it in the ratio 2 : 1.
H =

√3/2 × 9 × 2/3

3√3

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