Decimals and Fractions Practice Test 4

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Question : 33 of 40

Marks: +1, -0

If

1^3 + 2^3 + 3^3 + .... + 9^3 = 2025

, then the value of

(0.11)^3 + (0.22)^3 + ... + (0.99)^3

is closest to

3.695
2.695
0.3695
0.2695

Solution:

Here,

1^3 + 2^3 + 3^3 + .... + 9^3 = 2025

Now,

(0.11)^3 + (0.22)^3 + (0.33)^3 + ...... + (0.99)^3

= (0.11)^3 [1^3 + 2^3 + 3^3 + .... + 9^3]

= 0.001331 × 2025 = 2.695275 ≈ 2.695

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