Data Analysis Practice Test 1

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Directions ( 64-65): Bag A contains 4 white and 2 black Balls. Bag B contains 3 white and 3 black Balls. One ball is drawn at random from each bag, with replacement. Then the probability that:

Question : 64 of 65

Marks: +1, -0

Both the balls are white or both the balls are black is:

$7/12+5/12$
$(4/6+3/6)(2/6+3/6)$
$(4/6 . 3/6)+(2/6 . 3/6)$
$1-7/12 . 5/12$
None of these

Validate

Solution:

\table \Bag ,\White ,\Black;A, 4 ,2;B, 3 ,3

Both the balls are white or both the balls are black is:

(4/6 . 3/6)+(2/6 . 3/6)

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