Compound Interest Practice Test 1

Question : 8 of 40

Marks: +1, -0

A bacteria grows by 10% in the first two hours, then decreased by 10% in the next two hours. If the original count of bacteria is 10,000, find the count of bacteria after 4 hrs.

10,200
9,801
9,654
10,520
11,670

Validate

Solution:

Bacteria count after 4 hrs

=P(1+R/1 00)^2(1-R/100)^2

=10000(1+10/100)^2(1-10/100)^2

=10000(11/10)^2(9/10)^2

= 121 × 81 = 9,801

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