Average Practice Test 4

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Question : 8 of 40

Marks: +1, -0

The average of 5 consecutive integers starting from m is n. What is the average of 6 consecutive integers starting from (m + 2)?

${2n+5}/2$
$n + 3$
$n + 2$
${2n+9}/2$
None of these

Solution:

{m+m+1+m+2+m+3+ m+4}/5=n

5m+10=5n

m + 2 = n

or

m = n - 2

…(i)
∴ Required average

={m+2+m+3+m+4+m+5+m+6+m+7}/6

={6m+27}/6={2m+9}/2

={2(n-2)9}/2

[taking eq (1)]

={2n+5}/2

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