Area and Perimeter Practice Test 3

Question : 30 of 40

Marks: +1, -0

In a triangular field having sides 30 m, 72 m and 78 m, the length of the altitude to the side measuring 72 m is:

Solution:

s =

{30 + 72 + 78}/2

= 90 m
Area of the triangle =

√{90(90-30)(90-72)(90-78)}

√{90×60×18×12}

√{2×3×3×5×2×2×3×5×2×3×3×2×2×3}

= 2 × 2 × 2 × 3 × 3 × 3 × 5 = 1080

m^2

Required altitude =

{2×1080}/{72}

= 30 m

Go to Question:

Prev Question

Next Question