Area and Perimeter Practice Test 3

Area of the rectangular space = 8 × 6 = 48 $\mathit{c}{\mathit{m}}^2$
Now, new length = 8 × $\frac{125}{100}$ = 10 cm; New breadth = 6 × $\frac{125}{100}$ = $\frac{15}{2}$ cm
Since, new area = 10 × $\frac{15}{2}$ = 75 $\mathit{c}{\mathit{m}}^2$
Change in area = 75 – 48 = 27 $\mathit{c}{\mathit{m}}^2$
Required percentage = $\frac{27}{48}\times 100$ = $56\frac{1}{4}\%$