Area and Perimeter Practice Test 2

Question : 4 of 40

Marks: +1, -0

X is a point on side CD of a square ABCD such that CX = 5 cm. If area of the triangle ADX is 42

cm^2

. What is the length of the side of the square?

Solution:

Let side of the square = a cm; then

1/2

× a × (a - 5) = 42

⇒

a^2

– 5a – 84 = 0
⇒

a^2

– 12a + 7a – 84 = 0
⇒ a(a – 12) + 7 (a – 12) = 0
⇒ (a – 12) (a + 7) = 0
Hence, a = 12 cm

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