Algebra and Applications Test 3

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Question : 21 of 25

Marks: +1, -0

If

a^3 - b^3 - c ^ 3 - 3abc = 0

, then

a = b = c
a + b + c = 0
a + c = b
a = b + c

Solution:

a^3 - b^3 - c^3 - 3abc = 0

a^3 + (-b^3) + (-c^3) + (-3abc) = 0

a + b + c = 0

So,

a - b - c = 0

a = b + c

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