If \sqrt{16-6\sqrt7}=a+b\sqrt7 what can be the value of b?

Algebra and Applications Test 3

Question : 18 of 25

Marks: +1, -0

√{16-6√7}=a+b√7

what can be the value of b?

Solution:

√{16-6√7}=a+b√7

=√{(3)^2+(√7)^2 -2×3 √7}=a+b√7

=√{(3 - √7)^2} =a+b√7

⇒3-√7=a+b√7

⇒a=3,b=-1

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