Algebra and Applications Test 2

Question : 26 of 40

Marks: +1, -0

If a + b + c = 0, the value of

(a^2/{bc}+b^2/{ca}+c^2/{ab})

is:

Solution:

a + b + c = 0

Now,

(a^2/{bc}+b^2/{ca}+c^2/{ab})

={a^3+b^3+c^3}/{abc}=1/{abc}(3abc)

∵ a^3 + b^3 + c^3 = 3abc

a+b+c=0

Value of

(a^2/{bc}+b^2/{ca}+c^2/{ab})=3

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