Punjab Patwari 20 Nov 2016 Paper 2

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Question : 85 of 100

Marks: +1, -0

In Boolean Algebra this is a law of De-Morgan's Theorem:

AB + AC = (A + C) (A + B)
A+A.B=A
$\;{AB}↖{¯} = \;{A}↖{¯} + \;{B}↖{¯}$
A.1=A

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