Postal or Sorting Assistants Model Paper 7 With Solutions

(b) Here H×30 = 4×30=120°.
(Si nee initially the hour hand is at 4. ∴H = 4).
Required angle A = 90° and since, H x 30 > A° so, there will be two timings
Required time T $=\frac{2}{11}$ (H * 30 ± A) minutes past H.
∴One timing $=\frac{2}{11}$(4 x 30 + 90) minutes past 4
=$38\frac{2}{11}$ minutes past 4.
Or 4 : 38 approx.