Pipes and Cisterns Practice Test 3 with solutions

Time taken by Pipe ‘P’ = 3 hours
Time taken by Pipe ‘Q’ = 6 hours
Part of cistern filled by both P and Q in one hour
= $\frac{1}{3}+\frac{1}{6}$
= $\frac{2+1}{6}$ = $\frac{1}{2}$
So, time taken by both Pipe ‘P’ and ‘Q’ = 2 hours
So, time taken by Pipe ‘C’ 2 hours
Part of cistern filled by all three in 1 hour = $\frac{1}{3}+\frac{1}{6}+\frac{1}{2}$ = $\frac{2+1+3}{6}$ = $\frac{6}{6}$ = 1
So, if all the three pipes are opened simultaneously they will fill the cistern in 1 hour.