Pipes and Cisterns Practice Test 2 with solutions

Let the time taken by the leakage to empty the full tank = x hours
then $\frac{1}{10}-\frac{1}{\mathit{x}}$ = $\frac{1}{12}$
$\frac{1}{\mathit{x}}$ = $\frac{1}{10}-\frac{1}{12}$
$\frac{1}{\mathit{x}}$ = $\frac{6-5}{60}$
$\frac{1}{\mathit{x}}$ = $\frac{1}{60}$
x = 60 hours
A leakage can empty the full tank in 60 hours
Then a leak can empty $\frac{7}{15}$ th part of the filled tank in $\frac{7}{15}\times 60$ = 28 hours.