Pipes and Cisterns Practice Test 2 with solutions

Let x hours be the time taken by tap to fill the tank, then 2x hours will be the time taken by leakage to empty the tank.
In 1 hour the part filled when both are opened = $\frac{1}{\mathit{x}}-\frac{1}{2\mathit{x}}$ = $\frac{1}{2\mathit{x}}$
Hence, the tank will be filled in 2x hours when both are opened.
Now, 2x – x = 36
∴ x = 36 hrs.
Hence, tap alone will fill the tank in 36 hours.