Pipes and Cisterns Practice Test 1 with solutions

Question : 29 of 40

Marks: +1, -0

A cistern can be filled by two taps A and B in 4 hours and 6 hours respectively. When full, the tank can be emptied by a third tap C in 8 hours. If all the taps be turned on at the same time, the cistern will be full in:

3 hr. 48 min.
3 hr. 42 min
3 hr. 26 min.
3 hr. 18 min.

Validate

Solution:

In 1 hour the part filled by all the three pipes =

1/4 + 1/6-1/8

7/{24}

Hence, all the three pipes will fill the cistern in

{24}/7

hr. = 3 hrs. 26 min.

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