Oxford University MAT 2017 Solved Papers

Rewriting $\tan \mathit{x}=\frac{\sin \mathit{x}}{\cos \mathit{x}}$ gives . In order to satisfy this inequality we know that $\sin \mathit{x}$ cannot be negative, since $\cos \mathit{x}$ would then also be negative, but $\tan \mathit{x}$ would be positive. This rules out $\left(\mathit{d}\right)$ and $\left(\mathit{e}\right)$. If , then , so $\cos \mathit{x}\le 0$ and the answer is (c).