NTSE Stage 2 SAT 2019 Exam Question Paper

Question : 80 of 100

Marks: +1, -0

Two organic compounds ‘A’ and ‘B’ react with sodium metal and both produce the same gas ‘X’, but with sodium hydrogen carbonate only compound B reacts to give a gas ‘Y \ Identify ‘A’, ‘B \ ‘X’ and ‘Y’:

A = Ethylene, B = Ethyl alcohol,
X = Carbon dioxide, Y = Hydrogen
A = Ethyl alcohol, B = Acetic acid,
X = Hydrogen, Y = Carbon dioxide
A = Methyl alcohol, B = Ethyl alcohol,
X = Hydrogen, Y = Carbon dioxide
A = Acetic acid, B = Formic acid,
X = Carbon dioxide, Y = Hydrogen

Validate

Solution:

When alcohol i.e. ethanol (A) and acid i.e. acitic acid (B) reacts with a sodium metal, then it liberates hydrogen gas (X).

{2CH_3CH_2OH}↙{(\A)}+2Na→2CH_3CH_2O^{-}Na^{+}+H_2↙{(\X)}↑

{2CH_3COOH}↙{(\B)}+2Na→2CH_3COO^{-}Na^{+}+{H_2}↙{(\X)}↑

When an acid reacts with carbonates or bicarbonates, it liberates

CO_2

gas So, when acitic acid(B) reacts with

NaHCO_3

,it librates

CO_2(Y)

gas.

{CH_3COOH}↙{(\B)}+NaHCO_3→CH_3COO-Na_{+}+H_2O+{CO_2}↙{(\Y)}↑

Go to Question:

Prev Question

Next Question