NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 56 of 100

Marks: +1, -0

A line from one vertex A of an equilateral ∆ABC meets the opposite side BC in P and the circumcircle of ∆ABC in Q. If BQ = 4 cm and CQ = 3 cm, then PQ is equal to

7 cm
$4/3$ cm
$12/7$ cm
2 cm

Validate

Solution:

Since, we know that

\;\;{1}/{{PQ}}=\;\;{1}/{{BQ}}+\;\;{1}/{{CQ}}=\;\;{1}/{4}+\;\;{1}/{3}=\;\;{3+4}/{12}=\;\;{7}/{12}

∴PQ=12/7

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