NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 52 of 100

Marks: +1, -0

Sealed bottle containing some water is made up of two cylinders A and B of radius 1.5 cm and 3 cm respectively, as shown in the figure. When the bottle is placed right up on a table, the height of water intit is 15 cm, but when placed upside down the height of water is 24 cm. The height of the bottle is

25 cm
26 cm
27 cm
28 cm

Validate

Solution:

Let the height of cylinder A be h and height of cylinder B be H. Since, in both the situation, the volume of the water in the bottle remains same, then

π(2r)^{2}H+πr^{2}(15-H)=πr^{2}h+π(2r)^{2}(24-h)

π^{2}[4{H}+(15-{H})]=π{r}^{2}[{h}+4(24-{h})]

4{H}+15{H}-{H}={h}+4(24-{h})

3{H}+15={h}+96-4{h}

3{H}+15=96-3{h}

{H}+5=32-{h}

{H}+{h}=27{cm}

Go to Question:

Prev Question

Next Question