The value of \cosx^{0}-\sinx^{0}(0\leqx\leq45)

sometimes negative and sometimes positive

NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 47 of 100

Marks: +1, -0

The value of

\cosx^{0}-\sinx^{0}(0≤x≤45)

Solution:

\;\;{1}/{√{2}}<\cosx≤1\;\text"for"\;0≤x<45^{∘}

0≤\sinx<\;\;{1}/{√{2}}

for

0≤x<45^{∘}

It is clear from the graph that cos x > sin x when

0≤x<45^{∘}

∴\cosx-\sinx>0

Go to Question:

Prev Question

Next Question