NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 44 of 100

Marks: +1, -0

The odd natural numbers have been divided in groups as

(1,3);(5,7,9,11);(13,15,17,19,21,23),.....

Then the sum of numbers in the 10 th group is

Solution:

Since, the general term of sum of odd natural number in the group is

=n(2n)^{2}=4n×n^{2}=4n^{3}

Hence, the required sum of numbers in the 10th group

=4×10^{3}=4000

Go to Question:

Prev Question

Next Question