NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 41 of 100

Marks: +1, -0

Given that

1/7={0.142857}↖{–––––––––––}

which is a repeating decimal having six different digits. If x is the sum of such first three positive integers n such that

1/n=0.{abcdef}↖{––––––––}

,where a, b, c, d, e and f are different digits, then the value of x is

Solution:

1/7=0{.142857}↖{–––––––––}

The second positive integer whose reciprocal have six different repeating decimals is

1/13=0{.76923}↖{–––––––}

And the third positive integer whose reciprocal have six different repeating decimals is

1/21=0{.047619}↖{––––––––}

Therefore, the values of x are 7, 13, 21
Hence, the required sum is

=7+13+21=41

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