NTSE Stage 2 SAT 2018 Exam Question Paper

Question : 26 of 100

Marks: +1, -0

A hydrocarbon ‘A’

(C_3H_8)

on treatment with chlorine in presence of sunlight yielded compound ‘B’ as major product. Reaction of ‘B’ with aqueous KOH gave ‘C’ which on treatment with concentrated

H_2SO_4

yielded ‘D’. Hydrogenation of ‘D’ gave back ‘A’. The sequence of reactions involved in above conversion is:

Substitution, substitution, addition, dehydration
Substitution, substitution , dehydration, addition
Substitution, dehydration, addition, addition
Addition, substitution, dehydration, substitution.

Validate

Solution:

C_2H_8(A)

is propane.

(i)

CH_3CH_2CH_3+Cl_2{––––––––>}↖{\text "Sunlight"}CH_3CH_2CH_2Cl+HCl(\text "Substitution")

(A) (B)
(ii)

CH_3CH_2CH_2Cl+aq.KOH––>CH_3CH_2CH_2OH+KCl(Substitution)

(B) (C)
(iii)

CH_3CH_2CH_2OH{–––––––––––>}↖{conc.H_2SO_4}CH_3CH=CH_2+H_2O(Dehydration)

CH_3CH=CH_2+H_2{––––––––>}↖{\text "Ni/Pt/Pd"}CH_3CH_2CH_3(\text "Addition")

(D) (A)

Go to Question:

Prev Question

Next Question