NTSE Stage 2 SAT 2017 Question Paper

Question : 51 of 100

Marks: +1, -0

Three circular wires are attached in series such that, if one wire is rotated, other two also get rotated. If the diameter of a wire is 4/5 times that of immediate left wire and the left most wire rotates at the speed of 32 revolutions per minute, then the number of revolutions made by right most wire per minute will be-

Validate

Solution:

\D_1\N_1=\D_2\N_2

4/5 \x×32=16/25\x×\N_3

\N_2=40

Now,

\N_2\D_2=\N_3\D_3

40×{16\x}/25={16\x}/125×\N_3

\N_3=50

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