NTSE Stage 2 SAT 2017 Question Paper

Question : 20 of 100

Marks: +1, -0

. A metal ‘M' of moderate reactivity is present as its sulphide ‘X' . On heating in air, ‘X' converts into its oxide ‘Y' and a gas evolves. On heating ‘Y' and ‘X' together, the metal ‘M' is produced. ‘X' and ‘Y' respectively are—

‘X' = cuprous sulphide, ‘Y' = cuprousoxide
‘X' = cupric sulphide, ‘Y' = cupric oxide
‘X' = sodium sulphide, ‘Y' = sodiumoxide
‘X' = calcium sulphide, ‘Y' = calciumoxide

Validate

Solution:

2\Cu_2\S+3\O_2 {––––––––▸}↖{△ }2\Cu_2\O+2\SO_2

2\Cu_2\O+\Cu_2\S{––––––––▸}↖{△ }6\Cu+\SO_2

X → cuprous sulphid
Y → cuprous oxide

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