NTSE Stage 2 SAT 2017 Question Paper

Question : 17 of 100

Marks: +1, -0

1.80 g of glucose is dissolved in 36.00 g of water in a beaker. The total number of oxygen atoms in the solution is

Solution:

As per unitary method
Number of oxygen atoms will be

6/180×1.8=0.06 \NA

∴ In 36.0 gm of water, number of oxygen atoms are

\NA/18×36=2\NA

⇒ total number of oxygen atoms

=(0.06+2)\NA

=2.06\NA

=2.06×6.022×10^23

=1.2405×10^24

=12.405×10^24

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