NTSE Stage 2 SAT 2016 Question Paper

Question : 50 of 100

Marks: +1, -0

If Anish is moving along the boundary of a triangular field of sides 35 m, 53m and 66m and you are moving along the boundary of a circular field whose area is double the area of the triangular field, then the radius of the circular field is

\Take \π=22/7

$14√3 \m$
$3√14 \m$
$28√3 \m$
$7√3 \m$

Validate

Solution:

Area of ∆

=√{\s(\s-\a)(\s-\b)(\s-\c)}

Here

\s={\a+\b+\c}/2

={66+53+35}/2=154/2=77 \m

=√{77(77-66)×(77-53)×(77-35)}

=√{77×11×24×42}

=924 \m^2

\π\r^2=2(924)

\r^2={2×924×7}/22

\r^2=588

\r=14√3 \m

Go to Question:

Prev Question

Next Question