NTSE Stage 2 SAT 2016 Question Paper

Question : 41 of 100

Marks: +1, -0

On dividing a natural number by 13, the remainder is 3 and on dividing the same number by 21, the remainder is 11. If the number lies between 500 and 600, then the remainder on dividing the number by 19 is :

Validate

Solution:

When Divided by 13 leaves remainder 3
When Divided by 21 leaves remainder 3

13-3=21-11=10=\k

\LCM (13, 21) – \k = 546 – 10 = 536

536 = 19 ×8 + 4

∴ remainder = 4
So the remainder is 4.

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