NTSE Stage 2 SAT 2015 Question Paper

Question : 52 of 100

Marks: +1, -0

A right circular cylinder has its height equal to two times its radius. It is inscribed in a right circular cone having its diameter equal to 10cm and height 12cm, and the axes of both the cylinder and the cone coincide. Then, the volume (in

\cm^3

) of the cylinder is approximately

107.5
118.6
127.5
128.7

Validate

Solution:

\h=2\r(\given)

∆\AFE ~ ∆\ADC

∴

{12-2\r}/ \r=12/5

∴

\r=30/11\cm

Now, volume of cylinder

\π\r^2\h

=22/7×(30/11)^2×(2×30/11)

(∴

\h=2\r

)

=22/7×900/121×{2×30}/11

=127.50

∴ Option (c) is correct.

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